1) The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 2x-3 and g(x) = 3x+8. Find f(x) multiplied by g(x). 2) The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = x^2+x-20 and g(x)=x+5. Find f(x)/g(x) <-- (this is a fraction.) 3) Evaluate the piecewise function at x=-3 and x-11. 4) Find the inverse of the function. F(x) = 3x+7.

Answer:1)6x^2+7x-242) x-43)  f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-154)f'(x)=(x-7)/3Step-by-step explanation:1) f(x)=2x-3 g(x)=3x+8f(x)*g(x)=m(x)=(2x-3)(3x+8)=6x^2+16x-9x-24=6x^2+7x-242) f(x)=x^2+x-20 g(x)=x+5f(x)/g(x)=p(x)=(x^2+x-20)/(x+5)=> by finding the roots of f(x) we obtain =(x-4)(x+5)/(x+5)--->f(x)/g(x)=p(x)=(x-4)3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7 f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-154) If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back xy=3x+7(y-7)/3=x=--> f'(x)=(x-7)/3